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5x^2+6x-23=-6x-9
We move all terms to the left:
5x^2+6x-23-(-6x-9)=0
We get rid of parentheses
5x^2+6x+6x+9-23=0
We add all the numbers together, and all the variables
5x^2+12x-14=0
a = 5; b = 12; c = -14;
Δ = b2-4ac
Δ = 122-4·5·(-14)
Δ = 424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{424}=\sqrt{4*106}=\sqrt{4}*\sqrt{106}=2\sqrt{106}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2\sqrt{106}}{2*5}=\frac{-12-2\sqrt{106}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2\sqrt{106}}{2*5}=\frac{-12+2\sqrt{106}}{10} $
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